1/7y^2-3/7y=0

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Solution for 1/7y^2-3/7y=0 equation: 


y in (-oo:+oo)

(1/7)*y^2-((3/7)*y) = 0

(1/7)*y^2+(-3/7)*y = 0

1/7*y^2-3/7*y = 0

DELTA = (-3/7)^2-(0*1/7*4)

DELTA = 9/49

DELTA > 0

y = ((9/49)^(1/2)+3/7)/(1/7*2) or y = (3/7-(9/49)^(1/2))/(1/7*2)

y = 3 or y = 0

y in { 0, 3 }

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